Problem #4
March 8, 2008 – 3:22 amThis also can be done using using one of the built functions but lets try to do this using recursion.
let rec nr_elements l =
match l with
| [] -> 0
| x::xs -> 1 + nr_elements xs;;
nr_elements myList |> printf "Length: %d"
Just use forward recursion adding one to the result and then return zero at the base case (empty list).